Jpegloop - Revision history

Michael Murtaugh at 19:16, 23 February 2018

2018-02-23T19:16:41Z

2013-03-04T20:28:50Z

Apply to a directory of files

← Older revision		Revision as of 22:28, 4 March 2013
Line 77:		Line 77:
	for ((i=100;i>=1;i--))		for ((i=100;i>=1;i--))
	do		do

	name=$(printf "%03d\n" $((100-i)))		name=$(printf "%03d\n" $((100-i)))
	convert lastframe.jpg -quality $i output$name.jpg		convert lastframe.jpg -quality $i output$name.jpg

2013-03-04T20:28:29Z

Apply to a directory of files

← Older revision		Revision as of 22:28, 4 March 2013
Line 73:		Line 73:
	for j		for j
	do		do
	cp $j lastframe.jpg		cp $j lastframe.jpg

	for ((i=100;i>=1;i--))		for ((i=100;i>=1;i--))
	do		do

	name=$(printf "%03d\n" $((100-i)))		name=$(printf "%03d\n" $((100-i)))
	convert lastframe.jpg -quality $i output$name.jpg		convert lastframe.jpg -quality $i output$name.jpg
	# COPY THE CURRENT TO "lastframe.jpg"		# COPY THE CURRENT TO "lastframe.jpg"
	cp output$name.jpg lastframe.jpg		cp output$name.jpg lastframe.jpg


	done		done

2013-03-04T14:54:15Z

Apply to a directory of files

← Older revision		Revision as of 16:54, 4 March 2013
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	ffmpeg -f image2 -i output%03d.jpg -r 10 $j.mp4		ffmpeg -f image2 -i output%03d.jpg -r 10 $j.mp4
	</source>		</source>

			== Converting the images to a movie ==

			ffmpeg -f image2 -i output%03d.jpg -r 10 output.mp4

	== Apply to a directory of files ==		== Apply to a directory of files ==
			The whole thing can be wrapped in a "for" loop to process a whole bunch of input images at once.

	<source lang="bash">		<source lang="bash">
	#!/bin/bash		#!/bin/bash

2013-03-04T14:53:09Z

Basic Loop

← Older revision		Revision as of 16:53, 4 March 2013
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	</source>		</source>

	== ~~Basic Loop~~ ==		== Compressing the "lastframe" to perform an iterative compression ==

			The trick here is to keep a "lastframe" copy that can always be used as the input to the convert command.

	<source lang="bash">		<source lang="bash">
	cp $j lastframe.jpg		cp $j lastframe.jpg

2013-03-04T14:51:42Z

Fixing the filenames (zero padding with printf)

← Older revision		Revision as of 16:51, 4 March 2013
Line 30:		Line 30:
	007		007

			=== command substitution ===

	$() means "command substitution" -- or do what's inside the parentheses and then substitute the result. This can be used to store the result of running printf in a variable (to then use again)		$() means "command substitution" -- or do what's inside the parentheses and then substitute the result. This can be used to store the result of running printf in a variable (to then use again)

2013-03-04T14:51:13Z

Fixing the filenames (zero padding with printf)

← Older revision		Revision as of 16:51, 4 March 2013
Line 31:		Line 31:


	$() means "command substitution" -- or do what's inside the parentheses and then substitute the result. This can be used to store the result of running printf in a variable (to then use again)		$() means "command substitution" -- or do what's inside the parentheses and then substitute the result. This can be used to store the result of running printf in a variable (to then use again)

	<source lang="bash">		<source lang="bash">

2013-03-04T14:50:48Z

Fixing the filenames (zero padding with printf)

← Older revision		Revision as of 16:50, 4 March 2013
Line 27:		Line 27:
	printf can be used to "zero-pad" a number (ie make a good filename from a counting number)		printf can be used to "zero-pad" a number (ie make a good filename from a counting number)
	printf "%03d" 7		printf "%03d" 7
	outputs:		means "zero-pad" (add zeros) to always be 3 characters long, and outputs:
	007		007

2013-03-04T14:50:07Z

Fixing the filenames (zero padding with printf)

← Older revision		Revision as of 16:50, 4 March 2013
Line 25:		Line 25:
	== Fixing the filenames (zero padding with printf) ==		== Fixing the filenames (zero padding with printf) ==

	$() means "command substitution" -- or do what's inside the parentheses and then substitute the result		printf can be used to "zero-pad" a number (ie make a good filename from a counting number)
			printf "%03d" 7
			outputs:
			007


			$() means "command substitution" -- or do what's inside the parentheses and then substitute the result. This can be used to store the result of running printf in a variable (to then use again)

	<source lang="bash">		<source lang="bash">

2013-03-04T14:48:54Z

← Older revision		Revision as of 16:48, 4 March 2013
Line 1:		Line 1:
	== ~~Loop~~ ==		== Counting up ==
	~~Counting up...~~		<source lang="bash">
			for ((i=1;i<=100;i++))
			do
			echo $i
			done
			</source>

			== Counting down ==
	<source lang="bash">		<source lang="bash">
	for ((i=1;i<=100;i++))		for ((i=1;i<=100;i++))
Line 9:		Line 15:
	</source>		</source>

			== Doing something ==
			<source lang="bash">
			for ((i=1;i<=10;i++))
			do
			convert original.jpg -quality $i output$i.jpg
			done
			</source>

			== Fixing the filenames (zero padding with printf) ==

			$() means "command substitution" -- or do what's inside the parentheses and then substitute the result

	<source lang="bash">		<source lang="bash">
	for ((i=~~100~~;i>=1;i--))		for ((i=1;i<=10;i++))
	do		do

	name=$(printf "%03d\n" $i)		name=$(printf "%03d\n" $i)
	convert original.jpg -quality $i output$name.jpg		convert original.jpg -quality $i output$name.jpg